{"msg":"第四节 算法(数值算法与非数值算法)的选择与应用","code":200,"data":{"currentIndex":null,"examId":null,"examTime":null,"questionList":[{"id":"796239536395931649","title":"某部门邀请3位专家对12个项目进行评选,每个专家选了5个项目。评选的结果中,有a个项目被3人都选中,有b个项目被2个选中,有c个项目被1人选中,有2个项目无人选中。据此,可以推断(52)。","analyze":"本题考查数学应用(方程求解分析)能力。<br>根据题意,a,b,c都是非负整数,a+b+c=12-2=10①,3a+2b+c=3X5=15②。由2①- ②可得c-a=5。<br>a=0时,c=5,b=5,c=a+b;<br>a=1时,c=6,b=3,c>a+b;<br>a=2时,c=7,b=1,c>a+b;<br>a>2时,c>7,a+c至少为11,与a+b+c=10矛盾。<br>根据上述情况,可以推断供选答案D是正确的。<br>(按汉语常规,a、b、c应均是正整数,a=0的情况不存在,此时应有结论c>a+b)","multi":0,"questionType":1,"answer":"D","chooseItem":["796239537780051969"],"itemList":[{"id":"796239537683582977","questionId":"796239536395931649","content":" a>2","answer":0,"chooseValue":"A"},{"id":"796239537721331713","questionId":"796239536395931649","content":" b>5","answer":0,"chooseValue":"B"},{"id":"796239537750691841","questionId":"796239536395931649","content":" b为偶数","answer":0,"chooseValue":"C"},{"id":"796239537780051969","questionId":"796239536395931649","content":" c≥a+b","answer":1,"chooseValue":"D"}],"userAnswer":null,"userChooseItem":null,"answerCorrect":null,"userCollect":null}]}}